Chromium 51 which targets the spleen

We have negative one on the right. This means when you have to add 54 in order for both sides of equal. And we see that element over 54 is seen on.

I always look at the weight. We have 1 31 on the left. We have zero on the right, so we need to add This means a Xena must have weight of Okay, Now for C, they're saying fosters 32 decays by beta particle production. So, process story, too. It's element over 15 cases. We have beta particle production. So beta particle.

So let's figure it. Let's balance it out. So we have 15 on the left. For the atomic number, you have negative one.

So we have to add Right, so 16 when we look on the period table element number 16 is. So for now, let's look at the weight. We have 32 on the left. We have zero on the right, so I get the at 32 more so so for must have a weight of Different immune and non-immune lymphoid cell populations were tested for in vitro cytotoxicity against pre-labelled tissue culture target cells Ha 3 which originated from a tumour induced by murine sarcoma virus MSV in a CBA mouse.

Anti-Ha 3 peritoneal exudate and spleen cells showed significant specific cytotoxicity against these target cells. The subscripts must add up. The superscripts must add up.

The element is determined by the atomic number. Example of what I mean. I know the atomic number is supposed to go on the left hand side as a subscript and that can be done easily. The mass number is supposed to go on the left of the element symbol as a superscript which can't be done on these boards; therefore, I will write it as a superscript but on the right hand side of the symbol for the element.

This is a different kind of decay but it works this way. An electron from the K shell drops into the nucleus. One proton combines with the electron to make a neutron so we now have 23 protons and 28 neutrons.

Now you add up both sides. What mass must it have. We have 60 on the left and 60 on the right; therefore, the mass number must be 0. What is it that has a charge of -1 and mass of zero?

That must be an electron. So we would write? So first thing we need to do is utilize the periodic table to look up the atomic number for chromium, which is 24 and show it capturing electron. And we've got to make sure with any nuclear reaction that the atomic numbers and the mass numbers balance properly.

So when we capture an electron, whatever product we form, is going to have the same mass number as the parent particle that we started with. But as we can see, it's going to have one less In terms of the atomic number. Because when we had the negative one from the electron to the 24 for chromium. No, but with the 23, So we need to look up then element number 23, which is vanadium In , then would be the product of this nuclear reaction.

An answer choice be we're told that we have iodine that produces a beta particle. So we have to know what a beta particle is. And it is essentially a particle that behaves like an electron and it's released as a product of this reaction. So it's the atomic number on the periodic table for iodine, it's Okay, and again, when we're dealing with beta or an electron, we remember the mass numbers are not going to change for whatever product we produce here.

So the mass number Of the product here is going to be just as it was with the iodine. But because this is now a product along with the unknown product here, um the daughter particle that we form is going to have one more proton or one greater atomic number than.

Um the element involved here. So that would be zen in With its atomic number of Again, to keep everything balanced properly, Zenon has to be the daughter particle formed, Phosphorus element number 15 phosphorus 32, we're told also emits a beta particle.

And so once again, we know that the mass number is going to be the same for the daughter particle formed here, but we have to have one more proton, one greater atomic number. That's sulfur. So sulfur 32 will be the daughter particle formed.